Avi Wigderson is here for a year and it was a good opportunity to go back together to the question of diameter of polytopes. The diameter problem for polytopes is to determine the behavior of the maximum diameter of the graph
of a simple
-polytopes
with
facets. We gave this problem considerable attention over here. (For example, we devoted to it polymath3.)
Let me mention an interesting problem about a high dimensional generalization of the “polynomial Hirsh conjecture”.
Let be a simple
-polytope with
facets (or, more generally, the dual of a simplicial
-sphere with
vertices).
Is the following true:
Every polygon
in the graph of
with
edges is the boundary of a 2-chain
with
norm (sum of coefficients) at most a polynomial number
in
, and
?
One can be more ambitious and ask for a a representation of as the boundary of a polyhedral 2-ball
. (In this case the
norm is simply the number of
-faces of
.)
But I am not sure even about this question:
Does every induced polygon in a graph of a simple polytope
the boundary of some 2-ball
(in the 2-skeleton of
)?
Is it known?
Remarks: a) Of course we can consider the question for cycles of dimensions greater than . We want to understand the behavior of the function
such that for every simple
-polytope
with
facets we can represent every
dimensional cycle
with
, as the boundary of a
-dimensional chain
, such that
.
b) One can ask also for an analog for the revisiting path question. And c) restriction attention to (duals) of vertex-decomposable spheres also is reasonable. This question is related to systolic inequalities and to high-dimensional expanders. As always, comments are welcome (also regarding polymath3.)
Hi Gil,
You cannot hope in general for an embedded 2-disk. This is easy in dimension 4 (because of knots) but also false in higher dimension (you can essentially take suspensions of 4-dim examplex and look at the doubles of knots.)
Dear Karim, right! I should have noticed it 🙂
Also, it would seem to me that the method of your paper gives at least a subexponential bound for the first question. and it seems to be at least as hard as Hirsch.
Interesting! I would love to see the details.
I will tell you if you answer the Oberwolfach invitation for January…